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44u^2-16u-112=0
a = 44; b = -16; c = -112;
Δ = b2-4ac
Δ = -162-4·44·(-112)
Δ = 19968
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{19968}=\sqrt{256*78}=\sqrt{256}*\sqrt{78}=16\sqrt{78}$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16\sqrt{78}}{2*44}=\frac{16-16\sqrt{78}}{88} $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16\sqrt{78}}{2*44}=\frac{16+16\sqrt{78}}{88} $
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